分析 根據(jù)題意可得,點(diǎn)B和點(diǎn)B的對(duì)應(yīng)點(diǎn)B1關(guān)于原點(diǎn)對(duì)稱,據(jù)此求出B1的坐標(biāo)即可.
解答 解:∵△A1OB1是將△AOB繞原點(diǎn)O順時(shí)針旋轉(zhuǎn)180°后得到圖形,
∴點(diǎn)B和點(diǎn)B1關(guān)于原點(diǎn)對(duì)稱,
∵點(diǎn)B的坐標(biāo)為(2,1),
∴B1的坐標(biāo)為(-2,-1).
故選D.
點(diǎn)評(píng) 本題考查了坐標(biāo)與圖形變化-旋轉(zhuǎn),圖形或點(diǎn)旋轉(zhuǎn)之后要結(jié)合旋轉(zhuǎn)的角度和圖形的特殊性質(zhì)來(lái)求出旋轉(zhuǎn)后的點(diǎn)的坐標(biāo).